| 95 | | We have something like 420,000 exposures (from pzDownloadImfile for gpc1, with fault = 0). Ideally, at mhpcc, we should have one ota on one node, therefore the expected ota count on each node should be precisely 420,000 (the actual mean being 274682, the maximum being 376716, the minimum 201702). On average, we have a difference of (420,000 - 274,682) roughly 50,000 otas / node. If they were uniformly spread on the nodes, we would have somtehing like 50,000/59 = 850 exposures. |
| | 95 | We have something like 420,000 exposures (from pzDownloadImfile for gpc1, with fault = 0). Ideally, at mhpcc, we should have only one ota on one node, therefore the expected ota count on each node should be precisely 420,000 (the actual mean being 274682, the maximum being 376716, the minimum 201702). On average, we have a difference of (420,000 - 274,682) roughly 150,000 otas / node. If they were uniformly spread on the nodes, we would have somtehing like 2500 exposures/node (2500 is roughly 150,000 otas spread on 59 nodes). The last histogram shows a peak around 2500 which is precisely what we expect. |
